非線形連立方程式の解法

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SATOKI KABEYA
SATOKI KABEYA on 26 Jul 2022
Answered: Hernia Baby on 26 Jul 2022
0.05*cos(theta21) + 0.04*cos(theta22) = 0.07;
0.05*sin(theta21) + 0.04*sin(theta22) = 0.01235;
からtheta21,theta22を解きたいのですが、どのようにmファイルに記述すればよろしいでしょうか?

Answers (1)

Hernia Baby
Hernia Baby on 26 Jul 2022
fsolveを参考にしてみてください。
以下は上記関数の一例になります。
fun = @root2d;
x0 = [0,0];
x = fsolve(fun,x0)
Equation solved. fsolve completed because the vector of function values is near zero as measured by the value of the function tolerance, and the problem appears regular as measured by the gradient.
x = 1×2
0.3532 0.6061
function F = root2d(x)
F(1) = exp(-exp(-(x(1)+x(2)))) - x(2)*(1+x(1)^2);
F(2) = x(1)*cos(x(2)) + x(2)*sin(x(1)) - 0.5;
end

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