In simulink, debouncing

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명근 오
명근 오 on 10 Aug 2022
Answered: Muthukumar Ganesan on 21 Aug 2022
If u1>3, move on to the next condition. When sampling time is 1 second, if u1>3 for 3 seconds by de-bouncing method, we want to move on to the next condition. If u1 >3 in 1 second, but u1 < 3 in 2 seconds, the next condition is not passed.

Answers (1)

Muthukumar Ganesan
Muthukumar Ganesan on 21 Aug 2022
Hi,
Using stateflow, you can implement this with after function whereas using simulink counter logic has to be implemented.
Please find the attachements.
Thanks

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