How can I Perform bitxor operation in matrix?
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Assume You have two matrix A and B with even number of rows as shown below. I want the first column in A to undergo bitxor with the second column in B, and the second column in A with bitxor with first column in B. The same approach be applied with column 3 in A with column 4 in B as well as column 4 in A with third column in B.Assume you n even equal number of rows in both matrix. Is it possible to use for loop?
A=[1 2 3 4] and B=[11 22 33 44;3 4 5 6]
example bitxor(1,22),bitxor(1,4),bitxor(2,11),bitxor(3,44),bitxor(3,66),bitxor(4,33)
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Accepted Answer
Bruno Luong
on 22 Aug 2022
A=[1 2 3 4], B=[11 22 33 44;3 4 5 6],
C=zeros(max(size(A),size(B)))
C(:,1:2:end)=bitxor(A(:,1:2:end),B(:,2:2:end));
C(:,2:2:end)=bitxor(A(:,2:2:end),B(:,1:2:end));
C
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