how to make rectangle in circle?

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Sierra
Sierra on 19 Nov 2022
Commented: Matt J on 20 Nov 2022
I want to make rectangles in circle.
I know the radius, rectangle's width and length.
please let me know how to do this
thanks

Accepted Answer

Matt J
Matt J on 19 Nov 2022
Edited: Matt J on 19 Nov 2022
[X,Y]=ndgrid(-10:10);
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',1/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',5), scale(r,[1,1.5]));
plot(c,'FaceColor','none')
  4 Comments
Sierra
Sierra on 20 Nov 2022
Thanks again.
but My circle's origin point is not zero. so I added my circle's origin point.
width=0.0073;
length=0.0097;
circleRadius=0.0833;
[X,Y]=ndgrid(-circleRadius:width:circleRadius+width);
X(:) = X(:) + ARP_lon % origin x 126.7975
Y(:) = Y(:) + ARP_lat % origin y 37.5569
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',width/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',circleRadius), scale(r,[1,length/width]));
plot(c,'FaceColor','none'); %axis equal
but it didn't work well.
could you explain more?
Matt J
Matt J on 20 Nov 2022
width=1;
length=1.3;
circleRadius=10;
[X,Y]=ndgrid(-circleRadius:width:circleRadius+width);
r=arrayfun( @(x,y) nsidedpoly(4,'Center',[x,y],'Radius',width/sqrt(2)) , X(:),Y(:));
c=intersect(nsidedpoly(1000,'Radius',circleRadius), scale(r,[1,length/width]));
c=translate(c,ARP_lon,ARP_lat);
plot(c,'FaceColor','none'); axis equal

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More Answers (1)

Image Analyst
Image Analyst on 19 Nov 2022
See the FAQ:
Then plot it with plot and then for each x and y value you want find the end points of a line segment and use line() or plot() to draw the line from one side of the circle to the other. It's easy but if you really can't figure it out then write back.
  3 Comments
Image Analyst
Image Analyst on 20 Nov 2022
You do not ned to know the crossing/intersection coordinates of the vertical and horizontal lines inside the circle. All you need to know for the horizontal lines is the y value and the two points on the circle closest to that y value. Similar for the lines in the other direction. But it looks like @Matt J suggested a different approach and you accepted that so I won't proceed with my approach.
Sierra
Sierra on 20 Nov 2022
Thanks for your answer!

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