Help for engineering equations

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Nayan
Nayan on 24 Nov 2022
Commented: KSSV on 24 Nov 2022
Hello i want to solve this equation in which diffrent set of values needs to be selected upon finding specific physical property. I am unable to correlate the logic.

Accepted Answer

KSSV
KSSV on 24 Nov 2022
The logic sounds simple. LHS (theta) can be any physical property like critical temperature, critical pressure, boiling point temperature and critical volume; for each of these property the contants a to f are given in table. You need to just substitute molecular weight, M.
M = 44.01 ; % Co2 molecular weight
gama = 1.53 ; % specific gravity of co2
K = [544.4 0.2998 1.0555 -1.3478*10-3 -0.61641 0.0
4.5203*104 -0.8063 1.6015 -1.8078*10-3 -0.3084 0.0
1.206*10-2 0.20378 -1.3036 -2.657*10-3 0.5287 2.6012*10-3
6.77857 0.401673 -1.58262 3.77409*10-3 2.984036 -4.25288*10-3 ] ; % Table 1-4
a = K(:,1) ;
b = K(:,2) ;
c = K(:,3) ;
d = K(:,4) ;
e = K(:,5) ;
f = K(:,6) ;
theta = a.*M.^b.*gama.^c.*exp(d*M+e*gama+f.*M*gama) ;
theta would be a 4x1 array giving you critical temperature, critical pressure, boiling point temperature and critical volume respectively.
  2 Comments
Nayan
Nayan on 24 Nov 2022
I got it bro, I got it. Thank you
KSSV
KSSV on 24 Nov 2022
Thanks is accepting/ voting the answer.

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