More multiplication operations require less time
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I would expect the execution times for the 3 operations below to get longer and longer. Where have I misled myself? Is it an issue with tic/toc as the timing method, or something else?
A=rand(500,500,500);
tic;
A.*A;
toc;
tic;
A.*A.*A;
toc;
tic;
A.*A.*A.*A.*A.*A;
toc;
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Accepted Answer
Walter Roberson
on 29 Aug 2023
It is because you are not recording the output.
I introduced T0 here because I was noticing that in my tests, T1 (the first operation) was consistently slower than T2 (the second operation), and I suspected that time to parse or something similar was being allocated against the first operation. With the T0 introduced, the measured time for A.*A reduces.
A=rand(500,500,500);
tic;
T0 = A;
toc;
tic;
T1 = A.*A;
toc;
tic;
T2 = A.*A.*A;
toc;
tic;
T3 = A.*A.*A.*A.*A.*A;
toc;
8 Comments
Walter Roberson
on 30 Aug 2023
Oh, right, it makes sense for James to have done that work! (But it would also have made sense for John to have done it as part of his high precision packages.)
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