left and right sides have a different number of elements.

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Hi, i've this problem
i is a logical 5995x1... price and bubu have equal size
load('matlab_3Variable.mat');
price(i)=bubu;
Unable to perform assignment because the left and right sides have a different number of elements.
  6 Comments
Torsten
Torsten on 6 Jun 2024
Edited: Torsten on 6 Jun 2024
load('matlab_3Variable.mat');
price(i)=bubu(i)
price = 5995x1
1.0e+03 * 1.4645 1.4645 1.4645 1.4645 1.4645 1.4645 1.4645 1.4645 1.4645 1.4538
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would set the values of price to the values of bubu for which i has logical 1 and leave the other values of price unchanged.
But if it's what you want - we don't know.

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Answers (1)

Matlab Pro
Matlab Pro on 6 Jun 2024
This is simple - since the 'i' is a logical indexing vector and is not all 'true'
length(find(i)) % == 5948
ans = 0
Thus: price(i) is a [5948x1] matrix and you want it to hold "bubu" which is 5995 matrix --> impossible
This - can be easliy fixed (if this is your requested outcome) like that;
price(i)=bubu(i);
Unrecognized function or variable 'bubu'.
  2 Comments
Luca Re
Luca Re on 6 Jun 2024
hi, it's not correct because "price" and "bubu" can to have to different size
Stephen23
Stephen23 on 6 Jun 2024
Edited: Stephen23 on 6 Jun 2024
"it's not correct because "price" and "bubu" can to have to different size"
They do not need to be the same sizes:
A = rand(2,3)
A = 2x3
0.3686 0.1659 0.7087 0.4115 0.2469 0.8034
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B = rand(4,5)
B = 4x5
0.3748 0.3379 0.6675 0.3304 0.4606 0.1202 0.2557 0.4158 0.0023 0.7938 0.1573 0.9340 0.4140 0.4896 0.3321 0.8504 0.4113 0.6661 0.6588 0.1033
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X = [true,false,true,false,true]
X = 1x5 logical array
1 0 1 0 1
A(X) = B(X)
A = 2x3
0.3748 0.1573 0.3379 0.4115 0.2469 0.8034
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What is relevant is how many elements on the RHS you are trying to allocate to the LHS.

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