how to change a variable?

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Rengin
Rengin on 27 Apr 2015
Answered: Thorsten on 27 Apr 2015
clear all
clc
nrow=5;
ncolumn=3;
A=[12 28 35;42 14 30;16 25 13;21 34 12;32 18 26];
B=[14 26 18;17 41 32;19 23 34;36 38 17;25 18 16];
C=sum(A,2);
D=sum(B,2);
SumLast=zeros(nrow,1);
for i=1:nrow
for j=1:ncolumn
% if jth (2.) column in ith (3.) row in A matrix bigger than
% jth (2.) column in ith (3.) row in B matrix, I want to put ith
% (3.) row of D matrix in ith (3.) row of LastSum
if (A(i,j)>B(i,j))
SumLast(i)=D(i);
% Otherwise, I want to meet the condition below:
else
SumLast(i)=C(i);
end
end
end
% I want to have LastSum=[58 90 76 67 59] but instead
% I get LastSum=[58 86 54 67 59]
% How can i correct that script?
% Many Thanks!
  2 Comments
Michael Haderlein
Michael Haderlein on 27 Apr 2015
Sorry, I don't understand how you select the value you want to put to SumLast. In your loop, you overwrite the value two times, I guess this is not intended. Best would be to just place a breakpoint at your first for and then use single step mode (F10 to forward one line) and see what happens.
Rengin
Rengin on 27 Apr 2015
Basically if an element in A matrix is bigger than the corresponding element in B matrix, I make my selection from D matrix. Otherwise, from C matrix. If one element in a row in A matrix is bigger than the corresponding element in B matrix, without looking at other elements in the row, I go to the following row. When you execute the script and look at my example, you'll understand what I mean

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Answers (1)

Thorsten
Thorsten on 27 Apr 2015
SumLast = D;
ind = ~any(A>B, 2);
SumLast(ind) = C(ind);

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