Duffing equation:Transition to Chaos
3 views (last 30 days)
Show older comments
Athanasios Paraskevopoulos
on 15 Aug 2024
Edited: Swastik Sarkar
on 29 Aug 2024
The Original Equation is the following:
Let . This implies that
Then we rewrite it as a System of First-Order Equations
Using the substitution for , the second-order equation can be transformed into the following system of first-order equations:
Exploring the Effect of γ.
% Define parameters
gamma = 0.338;
alpha = -1;
beta = 1;
delta = 0.1;
omega = 1.4;
% Define the system of equations
odeSystem = @(t, y) [y(2);
-delta*y(2) - alpha*y(1) - beta*y(1)^3 + gamma*cos(omega*t)];
% Initial conditions
y0 = [0; 0]; % x(0) = 0, v(0) = 0
% Time span
tspan = [0 2000];
% Solve the system
[t, y] = ode45(odeSystem, tspan, y0);
% Plot the results
figure;
plot(t, y(:, 1));
xlabel('Time');
ylabel('x(t)');
title('Solution of the nonlinear system');
grid on;
% Plot the phase portrait
figure;
plot(y(:, 1), y(:, 2));
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
% Define the tail (e.g., last 10% of the time interval)
tail_start = floor(0.9 * length(t)); % Starting index for the tail
tail_end = length(t); % Ending index for the tail
% Plot the tail of the solution
figure;
plot(y(tail_start:tail_end, 1), y(tail_start:tail_end, 2), 'r', 'LineWidth', 1.5);
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
ax = gca;
chart = ax.Children(1);
datatip(chart,0.5581,-0.1126);
Then I used but the results were not that I expected for
My code gives me the following. Any suggestion?
% Define parameters
gamma = 0.35;
alpha = -1;
beta = 1;
delta = 0.1;
omega = 1.4;
% Define the system of equations
odeSystem = @(t, y) [y(2);
-delta*y(2) - alpha*y(1) - beta*y(1)^3 + gamma*cos(omega*t)];
% Initial conditions
y0 = [0; 0]; % x(0) = 0, v(0) = 0
% Time span
tspan = [0 3000];
% Solve the system
[t, y] = ode45(odeSystem, tspan, y0);
% Plot the phase portrait
figure;
plot(y(:, 1), y(:, 2));
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
% Define the tail (e.g., last 10% of the time interval)
tail_start = floor(0.9 * length(t)); % Starting index for the tail
tail_end = length(t); % Ending index for the tail
% Plot the tail of the solution
figure;
plot(y(tail_start:tail_end, 1), y(tail_start:tail_end, 2), 'r', 'LineWidth', 1.5);
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.35$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
ax = gca;
chart = ax.Children(1);
datatip(chart,0.5581,-0.1126);
3 Comments
Accepted Answer
Swastik Sarkar
on 29 Aug 2024
Edited: Swastik Sarkar
on 29 Aug 2024
Upon reviewing the paper linked in the question (https://www.colorado.edu/amath/sites/default/files/attached-files/good_sample_project_0.pdf), it specifies a time range of [0, 3000] and focuses on the initial and final few points for its plots, whereas the current solution plots the range [0, 200] with 3000 points, as indicated usinglinspace(0, 200, 3000) upon the entire duration. So, changing the code to the below one will give you desired plots.
% Define parameters
gamma = 0.35;
alpha = -1;
beta = 1;
delta = 0.1;
omega = 1.4;
% Define the system of equations
odeSystem = @(t, y) [y(2);
-delta*y(2) - alpha*y(1) - beta*y(1)^3 + gamma*cos(omega*t)];
% Initial conditions
y0 = [0; 0]; % x(0) = 0, v(0) = 0
tspan = [0 3000]; % Increase the number of points
% Solve the system with increased output refinement
[t, y] = ode45(odeSystem, tspan, y0);
% Define the tail (e.g., last 10% of the time interval)
extreme_tail_start = floor(0.9966 * length(t)); % Starting index for the tail
% Define the tail (e.g., last 10% of the time interval)
tail_start = floor(0.989 * length(t)); % Starting index for the tail
tail_end = length(t); % Ending index for the tail
% Define the head (e.g., first 10% of the time interval)
head_start = 1; % Starting index for the tail
head_end = floor(0.1 * length(t)); % Ending index for the tail
% Plot the phase portrait
figure
plot(y(head_start:head_end, 1), y(head_start:head_end, 2), 'LineWidth', 1.5);
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
% Plot the tail of the solution
figure
plot(y(tail_start:tail_end, 1), y(tail_start:tail_end, 2), 'LineWidth', 1.5);
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
% Plot the extreme tail of the solution
figure
plot(y(extreme_tail_start:tail_end, 1), y(extreme_tail_start:tail_end, 2), 'LineWidth', 1.5);
xlabel('x(t)');
ylabel('v(t)');
title('Phase-Plane $$\ddot{x}+\delta \dot{x}+\alpha x+\beta x^3=0$$ for $$\gamma=0.318$$, $$\alpha=-1$$,$$\beta=1$$,$$\delta=0.1$$,$$\omega=1.4$$','Interpreter', 'latex');
grid on;
% Adding a datatip for visualization (optional)
ax = gca;
chart = ax.Children(1);
datatip(chart,0.5581,-0.1126);
0 Comments
More Answers (0)
See Also
Categories
Find more on Line Plots in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!