how to do convolution without commands
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omar chavez
on 27 Nov 2011
Commented: Sai Jothsna Sri
on 7 Sep 2023
Hi, im trying to do convolution without any of the commands in matlab.
Just plain for, this is because im trying to use a code that can also be implemented on C.
So far I have this
x=[1 2 3]
h=[-1 0 3]
Z=[0]
[M,N]=size(x)
[L,O]=size(h)
A=N+O-1
for n=1:1:N
for o=1:1:O
y(n,o)=x(n)*h(o)
end
end
Accepted Answer
Chandra Kurniawan
on 27 Nov 2011
Hi, Omar. Do you seeking for 2D convolution code without Matlab toolbox command?? I have the code below
function B = convolve(A, k);
[r c] = size(A);
[m n] = size(k);
h = rot90(k, 2);
center = floor((size(h)+1)/2);
left = center(2) - 1;
right = n - center(2);
top = center(1) - 1;
bottom = m - center(1);
Rep = zeros(r + top + bottom, c + left + right);
for x = 1 + top : r + top
for y = 1 + left : c + left
Rep(x,y) = A(x - top, y - left);
end
end
B = zeros(r , c);
for x = 1 : r
for y = 1 : c
for i = 1 : m
for j = 1 : n
q = x - 1;
w = y -1;
B(x, y) = B(x, y) + (Rep(i + q, j + w) * h(i, j));
end
end
end
end
Save the following code with filename 'convolve.m'. And then create a new m-file and type this code :
clear; clc;
I = [4 4 3 5 4;
6 6 5 5 2;
5 6 6 6 2;
6 7 5 5 3;
3 5 2 4 4];
k = [0 -1 0;
-1 4 -1;
0 -1 0];
Hsl = convolve(I, k)
Watch at the result! You can also compare the result with the matlab toolbox command 'conv2'
Bnd = conv2(I,k,'same')
The both results are same :
Hsl =
6 3 -2 8 9
9 3 0 2 -3
2 0 2 6 -3
9 6 0 2 1
1 8 -6 5 9
Bnd =
6 3 -2 8 9
9 3 0 2 -3
2 0 2 6 -3
9 6 0 2 1
1 8 -6 5 9
>>
1 Comment
David Young
on 27 Nov 2011
This is a little more complex than necessary - you don't need the first loop that reflects A, just change the index computation in the second loop to reflect the mathematical definition of convolution.
More Answers (5)
Wayne King
on 27 Nov 2011
I take it when you say "without commands", you really are just saying without conv(). It appears to me you have 1-D vectors from your initial post. Specifically, you give the example:
x=[1 2 3];
h=[-1 0 3];
You can exploit the relationship between linear convolution, circular convolution, and the DFT by extending the length of your input vectors with zero-padding, multiplying their DFTs, and then taking the inverse DFT.
x = [1 2 3]';
h = [-1 0 3]';
N = length(x)+length(h)-1;
x1 = [x; zeros(N-length(x),1)];
h1 = [h; zeros(N-length(h),1)];
convxh = ifft(fft(x1).*fft(h1));
Compare convxh with
conv(x,h)
DI
on 16 Mar 2015
The first answer is not actually full size.
Full size will be like this:
% Written by Dizeng 3/15/2015. Full convolution.
function B = convolve(A, k)
[r,c] = size(A);
[m,n] = size(k);
h = rot90(k, 2);
center = floor((size(h)+1)/2);
Rep = zeros(r + m*2-2, c + n*2-2);
for x = m : m+r-1
for y = n : n+r-1
Rep(x,y) = A(x-m+1, y-n+1);
end
end
B = zeros(r+m-1,n+c-1);
for x = 1 : r+m-1
for y = 1 : n+c-1
for i = 1 : m
for j = 1 : n
B(x, y) = B(x, y) + (Rep(x+i-1, y+j-1) * h(i, j));
end
end
end
end
Hope it will be helpful to others...
3 Comments
Enrique de José María Flores Rodríguez
on 16 Mar 2021
Edited: Enrique de José María Flores Rodríguez
on 16 Mar 2021
Seem works good on a DICOM image on 2021, thank you !
SALVADOR CANAS
on 15 Jan 2018
Those convolutions are convolutions with padding=1, how do you do for padding=0?
0 Comments
Sk Group
on 25 Oct 2021
Convolution without conv function in MATLAB | Complete CODE | Explanation | Example And Output
For complete detailed post visit: https://www.swebllc.com/convolution-without-function-in-matlab/
0 Comments
VIGNESH B S
on 28 Jul 2022
% The code below is for convolution without conv command.
% Idea behind it is multiplying a element of x with every element in h and
% adding them with a shift.
% Eg: x = [1,2] and h = [4,5,6] say, h is transformed to [3,4,5,0] ; no.of
% zeros to add after h is given by min(len(x) ,len(h)) -1). als zero is
% added so problems with vector addn is removed. (ouput of conv is of same
% length as transformed h).
%then you perform x(1).*h = [4,5,6,0] and x(2).*h = [8,10,12,0] when x(i)
%if i>2 -> you add zeros to the result of x(i).*h in at index 1 and shift
%it. y = conv of x and h = [4,5,6,0] + [0,8,10,12].
clc
clear
x = input('Enter x [..] '); %getting input x and h
h = input('Enter h [..] ');
if length(x)>length(h)
temp_var = x;
x = h;
h = temp_var;
end
y = zeros(1,(length(x)+length(h)-1));
min_val = [length(x),length(h)];
r = min(min_val)-1; ;%minimum of x and h -1
hi = [h,zeros(1,r)];
for i = 1:length(x)
temp = x(i).*hi;
% disp(temp)
if i>=2
tempi = [zeros(1,i-1),temp(1:end-i+1)];
else
tempi = temp;
end
y = y + tempi;
end
disp('The convolution of x and h is:' );
disp(y)
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