Access the array index using find
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Pankaja Tanjore
on 2 Jul 2015
Commented: Titus Edelhofer
on 2 Jul 2015
Hello ,
I have an array A1 = [1 12 23 45]; and
second array A1_1 = [45 23];
I need to find the index of 45 and 23 in first array A1. I am using following function to do this find(a==a_1(1)) --Output =4 find(a==a_1(2)) --Output =3 I want to get this for multiple elements of array .
It would be grateful if you let me know the changes that are to be done to get it for multiple elements in an array.
Looking forward to hear from you at the earliest.
Thanks Pankaja
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Accepted Answer
Azzi Abdelmalek
on 2 Jul 2015
Edited: Azzi Abdelmalek
on 2 Jul 2015
a= [1 12 23 45];
b= [45 23]
out=arrayfun(@(x) find(a==x),b,'un',0)
Or using a for loop. The previous answer, also uses a loop.
for k=1:numel(b)
out{k}=find(a==b(k));
end
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More Answers (1)
Titus Edelhofer
on 2 Jul 2015
Hi,
I guess you are looking for this:
A1 = [1 12 23 45];
A1_1 = [45 23];
[~,idx] = ismember(A1_1, A1)
idx =
4 3
Titus
2 Comments
Titus Edelhofer
on 2 Jul 2015
Yes, you are right. In this case you would find only the first of the two 45 ...
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