How to add an index to graph title, legend, and output image without having to write everywhere the same number

MOTIVATION: I want that a predefined number be used in the following:

1) generation of a graph,

2) title of the graph,

3) legend of the graph,

4) name of the output file.

EXAMPLE: If I define the index equal to 2 as written in the script below,

INDEX=2;

x = 0:pi/100:2*pi;

y = sin(x-INDEX);

h=plot(x,y);

legend(h,'sin(x-INDEX)',1)

title('TEST INDEX','FontSize',26, 'FontName','Arial', 'FontWeight','bold')

print -dtiff -f1 -r600  OUTPUT_INDEX %or -dbitmap, -djpeg, -dtiff, -depsc

I WISH: that Matlab uses that value to generate the graph (as it already does), but also writes the name everywhere with that index. Thus the expectation is the following:

2) title of the graph: TEST 2 and not TEST INDEX

3) legend of the graph: sin(x-2) and not sin(x-INDEX)

4) name of the output file: OUTPUT_2 and not OUTPUT_INDEX

I wonder if someone could help me how to write these commands correctly.

Thanks for your attention

Emerson

Answer 1

[Fangjun Jiang]

what you need is num2str(INDEX) or sprintf()

f=figure(INDEX);
legend(h,sprintf('sin(x-%d)',INDEX),1);
title(['TEST ',num2str(INDEX));

The file name can be specified as ['OUTPUT_',num2str(INDEX)]

[Emerson De Souza]

Thank you a lot Fangjun,

your suggestion works correctly for the title and legend.

However, I wrote the following command line:

print -dtiff -f1 -r600 ['OUTPUT_',num2str(INDEX)];

and I obtain the following error:

print -dtiff -f1 -r600 ['OUTPUT_',num2str(INDEX)];

??? Error using ==> print at 325

What follows -f is not a Figure handle.

Do you know what I should do to correct this?

Thanks again

Emerson

[Fangjun Jiang]

To do that, you need to use the function format of print(), like

print(f,'-dtiff',['OUTPUT_',num2str(INDEX)])

[Emerson De Souza]

Thank you again Fangjun,

now it works well.

These command lines will

save a lot of my time.

Wish you a nice evening

Emerson