Error with cellfun using

I have a large code and I'm stuck on using cell arrays. I have some x values in cell array and i want to assign them with a function. There is a loop, function is working correct in first loop with first x cell array. But there is some error after second iteration, function didn't return true values.

x = 

      [-4.6250]    [-3.5750]
      [-3.8750]    [-2.2250]
      [-3.1250]    [-0.8750]
      [-2.3750]    [ 0.4750]
      [-1.6250]    [ 1.8250]
      [-0.8750]    [ 3.1750]
      [-0.1250]    [ 4.5250]
      [ 0.6250]    [ 5.8750]
      [ 1.3750]    [ 7.2250]
      [ 2.1250]    [ 8.5750]
      [ 2.8750]           []
      [ 3.6250]           []
      [ 4.3750]           []
      [ 5.1250]           []
      [ 5.8750]           []
      [ 6.6250]           []
      [ 7.3750]           []
      [ 8.1250]           []
      [ 8.8750]           []
      [ 9.6250]           []

My function is

f = cellfun(@(x) x.^2-3.*x+5,x);

I didn't initialize it as array or anything. Error is

Error using cellfun
Non-scalar in Uniform output, at index 31, output 1.
Set 'UniformOutput' to false.

Error in neg (line 1)
f = cellfun(@(x) x.^2-3.*x+5,x);

After I did 'UniformOutput' to false as it said, but then the function didn't return minus values. I want function to work for all x values. I have missing information about cell array. Can you give me any suggestion?

Answer 1

[Jan]

I do not see the problem.

C = {[-4.6250]    [-3.5750]; ...
     [-3.8750]    [-2.2250]; ...
     [-3.1250]    [-0.8750]; ...
     [-2.3750]    [ 0.4750]; ...
     [-1.6250]    [ 1.8250]; ...
     [-0.8750]    [ 3.1750]; ...
     [-0.1250]    [ 4.5250]; ...
     [ 0.6250]    [ 5.8750]; ...
     [ 1.3750]    [ 7.2250]; ...
     [ 2.1250]    [ 8.5750]; ...
     [ 2.8750]           []; ...
     [ 3.6250]           []; ...
     [ 4.3750]           []; ...
     [ 5.1250]           []; ...
     [ 5.8750]           []; ...
     [ 6.6250]           []; ...
     [ 7.3750]           []; ...
     [ 8.1250]           []; ...
     [ 8.8750]           []; ...
     [ 9.6250]           []};
F = cellfun(@(x) x.^2-3.*x+5, C, 'Uni', false);

This works as expected and the result is correct, even for the negative values:

x = -3.5750;
disp(x.^2-3.*x+5)
disp(F{1, 2})

[Ozge Moral]

I got what was my mistake.