divide data to 100 input files

I have a numeric data set as a 1xn (for example 1x32768) matrix, and I want to divide it into m files (for example 100 files) and making directories and send each file to corresponding directory. I did use the following code: reshape(Data,[],100); but problem is 32768 is not divisible to 100. is there any way for solve my issue? or I have to reduce my data to 32700? Any help is appreciated.

[Walter Roberson]

What do you want to have happen with the block of 68?

[Holden Caulfield]

They're part of my data, actually it is part of an assignment, so I have to compute mean, variance and mean standard deviation of each data sets. And write them in a file. So I wonder there is a way to avoid data loss.

[Walter Roberson]

If you need to do this for each data set, why are you grouping them into 100's ?

Answer 1

[Aritra Sasmal]

I don't understand why you want to reshape it but here's how you'd do it if you wanted to form a matrix like you have;

n=size(Data,1);
Mat=zeros(100,ceil(n/100));
Mat(:,1:floor(n/100))=reshape(Data(1:floor(n/100)),[],100);
Mat(1:(n%100),end)=Data(floor(n/100)+1:end);

This would create the 100 row matrix that you want.

However, you can just write a loop

i=1:ceil(n/100)

     put stuff in an array and save as ascii file and close the filw pointer

end

This would package the data into smaller files in a loop

[Holden Caulfield]

Thank for your help! But I believe reshape will create a matrix with 100 column, but your code supposed to create a matrix with 100 rows. Am I correct?

[Walter Roberson]

The code Aritra posted does have a conflict between 100 rows and 100 columns.

Answer 2

[Walter Roberson]

For numeric row matrix M,

   block = 100;
   blocked = mat2cell(M, 1, [block * ones(1, floor(M/block)), mod(M, block)]);

[Walter Roberson]

If you have a numeric matrix you want to rearrange into groups of fixed size, see buffer()