How can I find the sum of the perimeter of a matrix?
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Hi, I am wondering if I had a matrix [1,2,3;1,2,3;1,2,3] how I could find the sum of the perimeter. Thanks an advance.
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Accepted Answer
  dpb
      
      
 on 5 Aug 2016
        One way amongst any number...
>> M=[1,2,3;1,2,3;1,2,3];
>> I=ones(size(M)); I(2:end-1,2:end-1)=0;
>> S=sum(reshape(M.*I,1,[]))
S =
  16
>>
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More Answers (3)
  Stephen23
      
      
 on 5 Aug 2016
        
      Edited: Stephen23
      
      
 on 5 Aug 2016
  
      In one line is easy and very fast:
>> M = [1,2,3;1,2,3;1,2,3];
>> sum(sum([M([1,end],2:end-1),M(1:end,[1,end]).']))
ans =  16
5 Comments
  dpb
      
      
 on 10 Feb 2018
				[ ... Ricardo Florez Answer moved to comment since was a follow-up question on earlier Answer syntax ... dpb]
Hi. Why is it necessary to write two "sum" in the code: sum(sum(M(...)? Please see below:
the sum(M(:))-sum(sum(M(2:end-1,2:end-1)))
Thank you.
  dpb
      
      
 on 10 Feb 2018
				
      Edited: dpb
      
      
 on 11 Feb 2018
  
			Because sum(M(2:end-1,2:end-1)) is a row vector of the sums of the columns in the submatrix; to get the total have to then add those values. This is taken care of in the first sum by the use of the special syntax (:) that returns all elements of an array/matrix in a column so sum only needs to add the one column vector. There is no syntax in Matlab to apply the secondary indexing operation to the result of the first function call return; there've been many suggest the enhancement.
  Sanjay Zamindar
 on 28 Jun 2018
        
      Edited: dpb
      
      
 on 28 Jun 2018
  
      function final_sum = peri_sum(A)
size_row = size(A,1)
size_col=size(A,2)
Sum_of_first_row = sum (A(1, [1:1:end])); %base 
Sum_of_first_Colmn = sum(A([2:1:size_row],1))
%sum_col= sum(A([2:1:size_col], [1:size_col:size_col]));
Sum_of_last_column= sum(A([2:1:size_row],size_col))
sum_of_last_row = sum(A(size_row,[2:1:size_col-1]))
final_sum = sum_of_last_row+ Sum_of_last_column+Sum_of_first_Colmn+Sum_of_first_row
end
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