# Finding the indices of all minimum elements in a matrix

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### Accepted Answer

Image Analyst
on 29 Dec 2016

You can do it in one line of code. You just first need to decide if you want to locate occurrences of the global min, or if you want to find local mins (using imregionalmin), AND if you want a vector of logical indexes or a vector of actual indexes. Since you didn't say, I'm giving all 4 possibilities:

% Create sample data:

vec = [1,1,2,2,1,2,1,3,0,-1,4,0,3,-1,5];

% Find local mins as a logical index.

localMinIndexes = imregionalmin(vec)

% Find global mins as a logical index.

globalMin = min(vec);

globaMinIndexes = vec == globalMin

% If you want/need actual indexes, use find:

% Find local mins as actual indexes.

localMinIndexes = find(imregionalmin(vec))

% Find global mins as actual indexes.

globaMinIndexes = find(vec == min(vec))

##### 7 Comments

Image Analyst
on 14 Sep 2021

@james sinos that was an example for 2-D matrices. Both P and N are 2-D. Of course extractedN is 1-D. Not sure what you're looking for.

Here's another 2-D example where I also add the creation of a masked 2-D array where the location of the mins in m2 are also the same value in the same locations for m3.

% Demo by Image Analyst

clc; % Clear the command window.

close all; % Close all figures (except those of imtool.)

clear; % Erase all existing variables. Or clearvars if you want.

workspace; % Make sure the workspace panel is showing.

format short g;

format compact;

fontSize = 20;

% Create some arbitrary matrix.

m1 = 1000 * rand(8, 8)

% Create sample data with the min at multiple locations:

m2 = randi(9, 8, 8)

% Determine the min value:

minValue = min(m2(:))

% Find rows and columns where the min occurs:

[r, c] = find(m2 == minValue)

% Extract those locations of m1 into a new matrix

for k = 1 : length(r)

extractedN(k) = m1(r(k), c(k));

end

% Show 1-D extracted numbers in command window:

extractedN

% Make a 2-D matrix where everything is -99999 (or whatever you want)

% except for where there's a min in m2.

m3 = -99999 * ones(8,8);

m3(m2 == minValue) = minValue

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