ring (annulis) patch?
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Dear friends,
How do I make a 2D ring (annulus) patch? Is it possible to make it as a single patch with a single object handle?
I want plot several 2D objects in a figure. The objects behind the ring should be visible trough the hole, and I want to control the properties of the ring, e.g. with respect to transperancy, color and line style.
Sincerely, Peter.
Accepted Answer
More Answers (2)
Matt Tearle
on 20 Mar 2011
How's this? The patch is a single object, but you have to add the edge lines separately in this approach (otherwise you see the "branch cut" in the annulus).
% Make a plot to add the ring to
x = rand(100,1);
y = rand(100,1);
plot(x,y,'o')
% Make inner and outer boundaries
t = linspace(0,2*pi);
rin = 0.1;
rout = 0.25;
xin = 0.5 + rin*cos(t);
xout = 0.5 + rout*cos(t);
yin = 0.5 + rin*sin(t);
yout = 0.5 + rout*sin(t);
% Make patch
hp = patch([xout,xin],[yout,yin],'g','linestyle','none','facealpha',0.25);
hl1 = line(xin,yin,'color','k');
hl2 = line(xout,yout,'color','k');
6 Comments
Peter
on 20 Mar 2011
Walter Roberson
on 20 Mar 2011
Try putting a NaN between xout and xin, and between yout and yin.
Peter
on 20 Mar 2011
Walter Roberson
on 21 Mar 2011
I suspect this is due to the face color interpolation method that is set, especially with the leading nan (which you do not need, but a trailing nan might not hurt.) I cannot test out my speculations at the moment as I do not have graphic access right now.
Matt Tearle
on 21 Mar 2011
Yes, I thought of trying it with NaN, but that seems to confuse patch -- I think it's unable to work out where the "inside" of the region is. But I feel like a total idiot for not using the same trick for the boundary line.
Anyway, Peter, what's still missing/lacking from this approach? What do you mean by "pure hollow patches"?
Peter
on 21 Mar 2011
Sean de Wolski
on 19 Mar 2011
0 votes
2d or 3d?
For the 2d case just subtract circles. Learn how to make circles here: http://matlab.wikia.com/wiki/FAQ#How_do_I_create_a_circle.3F
You could use the same logic for the 3d "donut" using a formula found on wikipedia.
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