stopping a function after 30 iterations

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I have been working all day on this coding, i can not figure out how to stop it after 30 iterations
function root %finds the root of the equation F0fX(x) using newton-raphson method
clear all;
clc;
x=.8;
x=newton(x);
fprintf('root found at x= %10.8f\n',x);
function [y]=FofX(x)
%nonlinear function
y= x^2+1;
function [y]=derofF(x)
%derivative of the function
y=2*x;
function [x]=newton(x)
%code for finding with newton-raphson method
TOL=5e-09;
error=10*TOL;
%Top of the loop
iterations=0;
while(error>TOL)
delta=-FofX(x)/derofF(x);
x=x+delta;
iterations=iterations+1;
%check for the relative error condition:
%If too big, loop again;if small enough, end.
error=abs(delta/x);
end
fprintf('after%4.0f iterations\n',iterations)
thanks for any help
  2 Comments
Walter Roberson
Walter Roberson on 20 Apr 2012
What problems do you observe for the other functions?
David bondi
David bondi on 20 Apr 2012
the program just runs and will not stop unless i stop it and it errors in the delta=-FofX(x)/derofF(x) and x=newton(x)

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Accepted Answer

David bondi
David bondi on 21 Apr 2012
adding this to the correct line fixed the issue while(error>TOL&& (iteration<=30)
thank you

More Answers (1)

Hossein
Hossein on 21 Apr 2012
Hi, The function that you are using doesn't have any real root. If you change the function to x^2-1 it works perfectly fine.
  1 Comment
David bondi
David bondi on 21 Apr 2012
Thank you, However the equation i have to use is the x^2-1, the point of the exercise is to stop the program after 30 iterations

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