How to change the elements's position of a vector by N consecutive times?

Asked by vinicius lanziotti on 7 Dec 2017

Latest activity Commented on by vinicius lanziotti on 7 Dec 2017

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I want a loop that executes at one time only several combinations.

x = [1 2 3 4 5];

xp = randperm(numel(x), 2);

x(xp) = x(fliplr(xp))

>> test

x =

1 2 4 3 5

>> test

x =

1 3 2 4 5

1 Answer

回答者: Image Analyst 2017 年 12 月 7 日

採用された回答

Can't you simply use a for loop???

for k = 1 : N
    test
end

or you can use deal to do the swapping of indexes:

[x(xp(1)), x(xp(2))] = deal(x(xp(2)), x(xp(1)));

vinicius lanziotti 2017 年 12 月 7 日

ok. Thanks very much!