Clear Filters
Clear Filters

How to make conditional calculation?

5 views (last 30 days)
I have two vectors, contained in matrix M, each with a dimension of 1000 by 1. Each vector contains integer numbers. The values in one vector (call it vector two) is generated in way that it depends on the values in the other vector (call it vector one). I want to calculate the variance of the numbers in vector two if the values are below a certain threshold in vector one. I try to use the code below, but it returns nothing. Where am I making the mistake?
if M(:,1) < 0
var(M(:,2))
end

Accepted Answer

Image Analyst
Image Analyst on 24 Feb 2018
Maybe you mean this:
indexesToConsider = M(:, 1) < 0; % Consider the index if the M value is less than 0.
col2Variance = var(M(indexesToConsider, 2)); % Compute variance of only those rows.
  2 Comments
Snoopy
Snoopy on 24 Feb 2018
This the logical indexing Walter above mentions right? I now use it. Thanks a lot.
Image Analyst
Image Analyst on 25 Feb 2018
Yes, it's logical indexing in that it gives values of true and false. If you passed that into find() you'd get "linear indexes" which are the actual index numbers, like [1, 3, 5, 33, 45, etc.] instead of [1 0 1 0 1 0 0 etc.]

Sign in to comment.

More Answers (1)

Walter Roberson
Walter Roberson on 24 Feb 2018
if M(:,1) < 0
means the same thing as
if all(M(:,1) < 0)
which is probably not true.
Look up "logical indexing"
  2 Comments
Snoopy
Snoopy on 24 Feb 2018
Thanks. I now use the find function which returns the row numbers (or the row index I shall say?) where the condition for vector one is satisfied. Then I use these row numbers as the row subscript in vector two, and carry out the operation on this subset of the entries of vector two. Is this perhaps the correct approach?

Sign in to comment.

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!