gathering together specific elements from a column vector

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HI all, I have the matrix
A=
identif pairs time allpairs
[1] 'PDL12' 'JF2008' [ NaN]
[1] 'PDL12' 'JF2009' [-1.0000e-004]
[1] 'PDL12' 'MA2009' [ -0.0330]
[1] 'PDL12' 'MJ2009' [ -0.0268]
[1] 'PDL12' 'JA2009' [ -0.0264]
[1] 'PDL12' 'SO2009' [ -0.1913]
[1] 'PDL12' 'ND2009' [ -0.0415]
[1] 'PDL12' 'JF2010' [ -0.0168]
[1] 'PDL12' 'MA2010' [ -0.0502]
[1] 'PDL12' 'MJ2010' [ -0.0761]
[1] 'PDL12' 'JA2010' [ -0.0429]
[1] 'PDL12' 'SO2010' [ -0.0548]
[1] 'PDL12' 'ND2010' [ -0.0173]
[1] 'PDL12' 'JF2011' [ 0.0071]
[1] 'PDL12' 'MA2011' [ 0.0121]
[1] 'PDL12' 'MJ2011' [ -0.0727]
[1] 'PDL12' 'JA2011' [ -0.1628]
[1] 'PDL12' 'SO2011' [ 0.0056]
[2] 'PDL13' 'JF2008' [ NaN]
[2] 'PDL13' 'JF2009' [ 0.0218]
[2] 'PDL13' 'MA2009' [ -0.0037]
[2] 'PDL13' 'MJ2009' [ 0.0120]
[2] 'PDL13' 'JA2009' [ -0.0027]
[2] 'PDL13' 'SO2009' [-5.0000e-004]
[2] 'PDL13' 'ND2009' [ -0.2818]
[2] 'PDL13' 'JF2010' [ -0.0216]
[2] 'PDL13' 'MA2010' [ -0.0330]
[2] 'PDL13' 'MJ2010' [ -0.0468]
[2] 'PDL13' 'JA2010' [ -0.1309]
[2] 'PDL13' 'SO2010' [ -0.0318]
[2] 'PDL13' 'ND2010' [ -0.0014]
[2] 'PDL13' 'JF2011' [ -0.0779]
[2] 'PDL13' 'MA2011' [ 0.0224]
[2] 'PDL13' 'MJ2011' [ -0.0662]
[2] 'PDL13' 'JA2011' [ -0.2187]
[2] 'PDL13' 'SO2011' [ -0.0745]
and I want to group all the observations that correspond to JF2008 (JF=January and February) as follows
1 PDL12 JF2008
2 'PDL13' 'JF2008' [ NaN]
then all the observations that correspond to the next months
[1] 'PDL12' 'MA2008' [ -0.0330]
[2] 'PDL13' 'MA2008' [ 0.0218]
and so forth... . And then for the year 2009 similarly to 2008
thanks in advance
  2 Comments
Oleg Komarov
Oleg Komarov on 26 May 2012
Do you want to sort the table according to the third and then second row?
antonet
antonet on 26 May 2012
adrei bobrov gave the solution. thank you as well

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Accepted Answer

Andrei Bobrov
Andrei Bobrov on 26 May 2012
eg
k = cellstr(reshape(datestr(datenum(0,1:12,1,0,0,0),'m'),2,[])')
t = cellfun(@(x){x(1:2) x(3:end)},A(:,3),'un',0)
tt = cat(1,t{:})
[a,a] = ismember(tt(:,1),k)
[id,id] = sortrows([a,str2double(tt(:,2))],[2,1])
out = A(id,:)
OR
in this is case
out = A(reshape(reshape(1:size(A,1),[],2)',[],1),:)
  5 Comments
Oleg Komarov
Oleg Komarov on 27 May 2012
Say the matrix you posted is called A:
[trash idx] = sortrows([cat(1,A{:,1}) datenum(A(:,3),'mmm yyyy')],[2 1]);
A(idx,:)

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