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summation inside a "for loop"

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Nilanjan Roy
Nilanjan Roy on 29 May 2012
Hi I have a 100x100 matrix, A. I am doing the following:
q=0:0.1:50;sym k;
for j=1:length(q)
B1(j)=sum(exp(q(j)*A(k,1)), k=1..100);
end
for j=1:length(q)
B2(j)=sum(exp(q(j)*A(k,2)), k=1..100);
end
..................................
..................................
for j=1:length(q)
B100(j)=sum(exp(q(j)*A(k,100)), k=1..100);
end
The problem is perhaps with the command but I tried with both sum/symsum and some other variations. But always matlab gives one or the other error.
It would be very helpful if someone could suggest some "correct" command. Thanks a ton.
  1 Comment
Walter Roberson
Walter Roberson on 29 May 2012
http://matlab.wikia.com/wiki/FAQ#How_can_I_create_variables_A1.2C_A2.2C....2CA10_in_a_loop.3F

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Accepted Answer

Geoff
Geoff on 29 May 2012
I would expect this to work:
B = zeros(length(q), size(A,2));
for j = 1:length(q)
B(j,:) = sum( exp(q(j)*A) );
end
  3 Comments
Nilanjan Roy
Nilanjan Roy on 29 May 2012
thanks a lot man. i think i was unnecessarily using the symsum command where all i needed was "sum". thanks again.
Geoff
Geoff on 29 May 2012
Cool. Hope it's clear what's happening... sum will work along a single dimension. By default this is 1. That means it will sum columns. If it's 2, it'll sum rows, and so on.. Whatever you call strips in higher dimensions =) So we can compute the sum for every column at once (giving a 1x100 vector) and then shove that into the matching columns of B for a single row indexed by j. It would probably be more efficient if you flipped the dimensions of B and wrote a whole column at a time, but I kept it consistent with your matrix A for clarity.

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