For Loop
1 view (last 30 days)
Show older comments
Hi everybody!!
I´m trying to do a simple loop that looks like this:
for t = 1 : 1 : 5
[k_hat, b_T, values] = E_Test(y(t:1800+t-1), n_0);
a(:)=k_hat(t);
end
I just want that for every t, the variable "a" stores the variable k_hat but it is not working. I get the following error: Attempted to access k_hat(2); index out of bounds because numel(k_hat)=1.
If instead I try a(t)=k_hat; it just gives me one value of k_hat instead of 5 values. Could you please give me a hint on what am I doing wrong here?
Thank you so much!
0 Comments
Accepted Answer
Honglei Chen
on 30 May 2012
Apparently your k_hat is a scalar. It is probably changing in each iteration because the t you passed into E_Test is different. You can try the following in the loop
[k_hat(t), b_T, values] = E_Test(y(t:1800+t-1), n_0);
0 Comments
More Answers (0)
See Also
Categories
Find more on Loops and Conditional Statements in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!