# Meshgrid multi-valued function data

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Ahmed Zankoor on 12 Jun 2018
Edited: Ahmed Zankoor on 12 Jun 2018
If I have data z = f(x,y) which have at some (or all) (x,y) coordinates more than a value for z. How can I represent the corresponding z value for the X and Y mesh grid, where [X Y] = meshgrid(x,y). I also wonder how this is handled in sphere function. For example: >> [x y z] = sphere(50) , surf(x,y,z) Since x,y,z meshgrids are not in the normal format of mesh grids?
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Ahmed Zankoor on 12 Jun 2018
Edited: Ahmed Zankoor on 12 Jun 2018
Thank you Rik, I got your point for sphere. What I can not understand is the meshgrid part, how can we express (x1,y1,z1) and (x1,x2,z2) using the same mishgrid X,Y matrices. Take this for example:
[X Y] = meshgrid(x,y);
Z = - sqrt(radius^2 - X.^2 - Y.^2);
Z(imag(Z)~= 0) = 0 ;
surf(X,Y,Z)
Z(imag(Z)~= 0) = 0 ;
surf(X,Y,Z)
end}
What if I want to surf both halves of the sphere ??

Rik on 12 Jun 2018
You should use hold on to plot multiple parts. The code below is a fix to your code.
[X,Y] = meshgrid(x,y);
Z = sqrt(radius^2 - X.^2 - Y.^2);
Z(imag(Z)~= 0) = 0 ;
%set coordinates outside of the sphere to the edge
phi=atan2(Y,X);
%put the two halves together
Z = [Z,-Z];
X = [X,X];
Y = [Y,Y];
figure(1),clf(1)
surf(X,Y,Z)
Ahmed Zankoor on 12 Jun 2018
Edited: Ahmed Zankoor on 12 Jun 2018
Thank you so much Rik. So this is my point, meshgrid 2D matrices must be single-valued (single value of z corresponding to each (x,y)), otherwise, we should use multiple surfaces (different Z matrices for the same X and Y).