- loop over the length of the data vector.
- detect any discontinuities (e.g. difference/offset, or some other metric).
- shift the remaining data by the detected offset (use indexing).
Formatting data using an if function
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Benedikt Wessel
on 21 Sep 2018
Commented: Benedikt Wessel
on 22 Sep 2018
Hello everybody, how can I adjust the data, so that the purple curve will always be connected? The next purple section should start at the end of the section before.... I've no clue how to do that. I really need help, because of this thing I'm not able to finish my bachelor thesis. Thanks guys.
(Ignore the legend)
C=cumsum(diffE,'omitnan'); % needed Capacity
Cbmax= 1000; % in MWH, max. capacity of the battery storage
Cbmin= 100; % in MWh, deep charge border
imax= C>=Cbmax-Cbmin; % find where C is larger than the Capacity
imin= C<=0; % find where C is =0
C(imax) = Cbmax-Cbmin; % if C is larger than Cbmax: C=Cbmax
C(imin) = Cbmin-Cbmin; % if C is smaller than Cbmin: C=Cbmin
Cres=cumsum(diffE,'omitnan');
for k=1:length(Cres)-1
if Cres(k)>(Cbmax-Cbmin) && Cres(k)>Cres(k+1)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
if Cres(k)>(Cbmax-Cbmin) && C(k)<(Cbmax-Cbmin)
C(k+1)=C(k)-Cres(k)+Cres(k+1);
end
end
0 Comments
Accepted Answer
Stephen23
on 21 Sep 2018
Edited: Stephen23
on 22 Sep 2018
"how can I adjust the data, so that the purple curve will always be connected?"
Something like this:
for k = 2:numel(vec)
d = diff(vec(k-1:k))
if abs(d)>tol % pick a tolerance, or some metric
vec(k:end) = vec(k:end)-d;
end
end
I just tried this on a fake data vector:
tol = 2;
vec = [0,1,2,3,4,10,11,12,13];
giving:
>> vec
vec =
0 1 2 3 4 4 5 6 7
You could fine-tune the algorithm so that it includes an offset of the same sign as d, but with magnitude tol. Also it would pay to do some reading into detecting discontinuities:
3 Comments
Stephen23
on 22 Sep 2018
Edited: Stephen23
on 22 Sep 2018
"But unfortunately the diff functions is always in an endless loop"
Check if you have any other functions named diff:
which diff -all
And if so, rename them. Also ensure that you do not have any variables name diff. Note that diff is not strictly required, you could do this:
d = vec(k)-vec(k-1)
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