Using Delaunay triangulation to approximate the area
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Hi, 
I try to use delaunay triangulation but it also connected the boundary point 
As you  an see the X shape, thats what I wanted only, not the square too.
thank you 
2 Comments
  John D'Errico
      
      
 on 14 Nov 2018
				
      Edited: John D'Errico
      
      
 on 14 Nov 2018
  
			Why did you need to ask this question twice? As I showed the last time you asked the question, you cannot use a Delaunay triangulation to do what you want, at least not without understanding how to code an alpha shape.
  madhan ravi
      
      
 on 14 Nov 2018
				please don‘t ask the same question twice , this discourages the answerers who answer the question
Answers (1)
  KSSV
      
      
 on 14 Nov 2018
        xy = rand(5000,2);
k = (sqrt(sum((xy - [1 .5]).^2,2)) < 0.3) | ...
    (sqrt(sum((xy - [0 .5]).^2,2)) < 0.3) | ...
    (sqrt(sum((xy - [0.5 1]).^2,2)) < 0.3) | ...
    (sqrt(sum((xy - [0.5 0]).^2,2)) < 0.3);
xy(k,:) = [];
x = xy(:,1) ; y = xy(:,2) ; 
idx = boundary(x,y) ;  % gives boundary 
plot(x,y,'.r')
hold on
plot(x(idx),y(idx),'b')
A = polyarea(x(idx),y(idx))
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