problem with function handle
1 view (last 30 days)
Show older comments
alpha
alpha =
function_handle with value:
@(z)(z-b)/a
>> qa
qa =
function_handle with value:
@(z)sqrt((1./alpha.^2)-p.^2)
>> t = integral(qa,0,3)
Undefined operator '.^' for input arguments of type 'function_handle'.
Error in @(z)sqrt((1./alpha.^2)-p.^2)
Error in integralCalc/iterateScalarValued (line 314)
fx = FUN(t);
Error in integralCalc/vadapt (line 132)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 75)
[q,errbnd] = vadapt(@AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
0 Comments
Accepted Answer
madhan ravi
on 7 Jan 2019
Edited: madhan ravi
on 7 Jan 2019
EDITED
syms z
a=1; % an example datas
b=2;
p=3;
alpha=(z-b)/a;
qa=sqrt((1./(alpha.^2)-p.^2));
t = integral(matlabFunction(qa),0,3)
5 Comments
More Answers (0)
See Also
Categories
Find more on Matrix Computations in Help Center and File Exchange
Products
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!