Traversing an image matrix columnwise

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Hi guys i wanna traverse a matrix of an image column wise ie. it should consider first column and visit all the rows of that column and so on using for loops. Plz help me if u know the logic or code.

Accepted Answer

Josh
Josh on 31 Mar 2011
If I understand your question, the solution is a nested for loop along the lines of
[rows,cols] = size(Matrix);
for col = 1:cols
for row = 1:rows
work with Matrix(row,col);
end
end
  2 Comments
MechtEngineer
MechtEngineer on 31 Mar 2011
Exactly the same as mine above, except neater!

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More Answers (2)

MechtEngineer
MechtEngineer on 31 Mar 2011
I think you would want the following, assuming an m x n matrix A(row x column) with position of each array point (i,j)
for j = 1:size(A,2) % for each column
for i = 1:size(A,1) % for each row
% put your operation in here - I am just adding 1 to each pixel as an eg.
A(i,j) = A(i,j) + 1;
end
end

David Young
David Young on 31 Mar 2011
Linear indexing uses columnwise ordering, so as long as you don't need the row and column indexes explicitly, you can do
for k = 1:numel(A)
% operate on A(k)
end
It might be even better to consider whether you can vectorise the operation and avoid the loops altogether.
  1 Comment
MechtEngineer
MechtEngineer on 31 Mar 2011
Impressive solution! That really shortens the code required, and does the same thing.
And yes, as David Young says above, if you vectorise (or make the desired operations into matrices to add, subtract, multiply, correlate, etc) the operation, it will be quicker than "for" loops - I tried it recently, and my code ran 5 times faster!

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