Clear Filters
Clear Filters

BVP4c Solving two equations simultaneously

3 views (last 30 days)
Taylor Nichols
Taylor Nichols on 24 Jan 2019
Answered: Torsten on 25 Jan 2019
Say for example I have an 4th order ODE
y''' = A*y''+y
on the boundary [0 1] with the BC
y(0) = 1; y'(0) = 0; y(1) = 2; y'(1) = 0
I have my code setup like this.
init = bvpinit(linspace(0,1,10),[0,0,0,0]);
sol = bvp4c(@rhs_bvp, @bc_bvp, init);
x1 = linspace(0,1,100);
BS = deval(sol, x1);
function [ rhs ] = rhs_bvp( x, y )
A = 10;
rhs = [y(2);
y(3);
y(4);
A*y(3)+y(1)];
end
function [ bc ] = bc_bvp( yl, yr)
bc = [yl(1) - hi;
yl(2);
yr(1) - ho;
yr(2)];
end
Now Say I want to add another equation to solve simultaneously
V' = y
on the same boundary with BC
V(0) = 0; V(1) = 1
How would I go about including this new equation into this solver?
  1 Comment
David Goodmanson
David Goodmanson on 25 Jan 2019
Hi Taylor,
If you start with (your original expression was a typo)
y'''' = A*y''+ y
and plug in y = V', you obtain a fifth order differential equation. But now you have six boundary conditions,which appears to be one too many.

Sign in to comment.

Answers (1)

Torsten
Torsten on 25 Jan 2019
init = bvpinit(linspace(0,1,10),[0,0,0,0,0]);
sol = bvp4c(@rhs_bvp, @bc_bvp, init);
x1 = linspace(0,1,100);
BS = deval(sol, x1);
function [ rhs ] = rhs_bvp( x, y )
A = 10;
rhs = [y(2);
y(3);
y(4);
A*y(3)+y(1);
y(1)];
end
function [ bc ] = bc_bvp( yl, yr)
bc = [yl(1) - hi;
yl(2);
yr(1) - ho;
yr(2)
yl(5)];
%or yr(5)-1.0];
end

Categories

Find more on Programming in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!