How to solve loop equation with given data
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Dear all,
I want to solve the equation below.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/208120/image.jpeg)
first column of excel sheet is 'a' and 2nd column is 'b' coresponding to 'a'. For each a, there is m in the interval 0 to 3 with increment of 0.01 (m=0:0.01:3). How to solve ?
6 Comments
Adam Danz
on 13 Mar 2019
The reason it stopped working is because you changed the size of 'm' but didn't change the size of 'eff'. I added a solution below that corrects this and allows you to use any size of 'm' without needing to change the size of 'eff'.
Answers (1)
Adam Danz
on 13 Mar 2019
Edited: Adam Danz
on 25 Mar 2019
(continuing from the comments under the question to that the question is answered).
The more responsible way to initialize the loop variable is by using variables rather than hard-coding the variable size.
a = 1:1000;
b = 1:1000;
m = 0:0.01:3
n = 421; %number of loops
eff = zeros(n,length(m)) %here we use 'n' and the size of 'm' to define 'eff'
for i=1:n
eff(i,:) = ((0.65.*(a(i)-m-0.3).*b(i)))./10 ;
end
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