Can I divide a linear array by a number which larger than its size ?

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I am having a cell array. Each element of the cell array is a linear array . These arrays are of different sizes. when diving each array to some equal parts then I am not getting consistent parts. Suppose I want to divide each cell array by 20. When the size is greater than 20 then its ok. but when less than 20 then I am not getting any consistent parts. I want to divide each linear array to 20 equal parts. whatever the size is I dont want any padding of values. If the array size is 1×17 and diving with 20 will give 20 equal parts . The partition size will be less than 1. How can I do this ?
Zara Khan
Zara Khan on 16 Mar 2019
I am getting "cell array.png' cell array. Now I want to divide each cell equally to 20 partitions
Image Analyst
Image Analyst on 16 Mar 2019
Unless you want to do some interpolation/resizing, you can't because each array in each cell is not a multiple of 20.

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Answers (2)

KSSV on 16 Mar 2019
You interpolate your data into your desired size and then reshape. Read about interp1.
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Zara Khan
Zara Khan on 16 Mar 2019
how can I handle an entire cell array with this ? Suppose my first cell contains an array of size 1×17, diving with 20 will give a size of 0.85. Is this possible to do here ? Next cell contains 1×31 , diving with 20 again, next cell is 1×131 again diving with 20. Cell array contains 16 colums and 1000 rows . How can I loop over this process? Please help.

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Walter Roberson
Walter Roberson on 16 Mar 2019
Next20 = @(V) ceil(length(V)/20) * 20;
Interp20 = @(V) interp1(V, linspace(1, length(V), Next20(V)));
Split20 = @(V) mat2cell(V, 1, 20*ones(1, length(V)/20));
new_cell = cellfun( @(V) Split20(Interp20(V)), cell_array, 'Uniform', 0);
Zara Khan
Zara Khan on 17 Mar 2019
Error using zeros
Size inputs must be scalar.
Error in @(v,N)FirstN([v(:).',zeros(1,N)],N).'
Error in @(v)PadN(v,len)
Error in partition (line 67)
A = cellfun(@(v) PadN(v, len), A, 'uniform', 0);
I am always getting this error

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