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Creating Timetables: Error Message in SampleRate

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FW
FW on 18 Apr 2019
Commented: Peter Perkins on 3 May 2019
Hello, I am trying to use a suggested function to generate a timetable with a sampling frequency of 200 Hz.
tt = timetable(rand(12,1),'SampleRate', 200)
I get an error: Invalid parameter name: SampleRate. This is MATLAB 2017b.
How do we get the desired sample rate?
Thanks.

Accepted Answer

Adam Danz
Adam Danz on 18 Apr 2019
Edited: Adam Danz on 19 Apr 2019
Here's a link to the 2017b documentation for timetable().
You'll see that there is no 'SampleRate' property. That property appeared first in r2018b.
Here's how to achive your example for releases before and after 2018b.
% 2018b or more recent
data = rand(12,1);
sampleRate = 200; %hz
tt = timetable(data,'SampleRate', sampleRate);
% prior to 2018b
timeSamples = seconds(0 : 1/sampleRate : (size(data)-1)/sampleRate);
tt = timetable(timeSamples', data);

  2 Comments

FW
FW on 19 Apr 2019
Thank you. I will try to update to 2018b.
Peter Perkins
Peter Perkins on 3 May 2019
Adam is right, but usually this
seconds((0:(size(data)-1))/sampleRate)
is better numerically.

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