fourier series of this function
1 view (last 30 days)
Show older comments
i want the fourier seris of function:
my code:
clear all
clc
syms x
f=(x+2).*(x>-2)-(x+2).*(x>-1)+(1).*(x<=1)-(1).*(x<=-1)+(2-x).*(x>1)-(2-x).*(x>=2);
N=10;
a_0=(1/pi)*int(f*cos(0*x),-pi,pi)
for n=1:N
a_n(n)=(1/pi)*int(f*cos(n*x),-pi,pi);
b_n(n)=(1/pi)*int(f*sin(n*x),-pi,pi);
end
a_n
b_n
f_new=a_0/2;
for n=1:N
f_new=f_new+a_n(n)*cos(n*x)+b_n(n)*sin(n*x);
end
subs(f_new,x,5)
subs(f,x,5)
the error:
Error using symengine
Invalid integrand.
Error in sym/int (line 162)
rSym = mupadmex('symobj::intdef',f.s,x.s,a.s,b.s,options);
Error in Untitled3 (line 7)
a_0=(1/pi)*int(f*cos(0*x),-pi,pi)
my function:
2 Comments
infinity
on 27 Jun 2019
Hello,
It is seen that the function "f" is not easy for Matlab to find it intergrand by using the fucntion "int". Maybe, you should try to split the piecewise function "f" into some small intervals, for example, [0, -2], [-2, -1], [-1, 1], .... Then, you can get the integral over these intervals.
Answers (0)
See Also
Categories
Find more on Fourier Analysis and Filtering in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!