Group maths on for loop

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DARLINGTON ETAJE
DARLINGTON ETAJE on 8 Aug 2019
Edited: Guillaume on 8 Aug 2019
I am trying to solve this
omegas=0:1:10;
RR=40:70;
d=90;
for i=1:length(omegas)
for c=1:length(RR)
gg=d+(omegas.*RR);
end
end
for every value of omegas, I want to calculate gg. The idea is that gg should be a 31 by 11 matrix. Means that each omegas is calculated with all values of RR
  5 Comments
Guillaume
Guillaume on 8 Aug 2019
this is an easier way of looking at the problem
Not really, it's exactly the same issue. qq is a vector, so you still have a vector that you're trying to store in a scalar.
However, I've understood what you're asking from your description. Sometimes, explaining in words is better than broken code.

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Answers (2)

Adam
Adam on 8 Aug 2019
Edited: Adam on 8 Aug 2019
omegas=0:1:10;
RR=40:70;
d=90;
numOmegas = numel( omegas );
numRR = numel( RR );
gg = zeros( numOmegas, numRR );
for i=1:numOmegas
for c=1:numRR
gg(i,c) =d+(omegas(i).*RR(c));
end
end
You could do it perfectly fine without a loop at all though too probably.
  1 Comment
DARLINGTON ETAJE
DARLINGTON ETAJE on 8 Aug 2019
please the codes with the real problem below

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Guillaume
Guillaume on 8 Aug 2019
Edited: Guillaume on 8 Aug 2019
The vectorised version of what you intended with your loop (but didn't achieve):
R=15;
r=5;
epsilon=100;
delta=(R-r)*(epsilon/100);
Theta = 5:10005; %a ROW vector
omega_b1 = (1:9)'; %a COLUMN vector. The two vectors must be along different dimensions
x_b1 = delta*cos(omega_b1) + r*cos(Theta); %automatic expansion of compatible arrays
y_b1 = delta*sin(omega_b1) - r*sin(Theta);
Vb_x1 = -r*Theta.*sin(Theta) - (R - r)*epsilon*omega_b1.*sin(omega_b1)/100;
Vb_y1 = -r*Theta.*cos(Theta) + (R - r)*epsilon*omega_b1.*cos(omega_b1)/100;
ab_x1 = -r*Theta.^2.*cos(Theta) - (R - r)*epsilon*omega_b1.^2.*cos(omega_b1)/100;
ab_y1 = r*Theta.^2.*sin(Theta) - (R - r)*epsilon*omega_b1.^2.*sin(omega_b1)/100;
I've removed a lot of unnecessary brackets.
For how this works, see compatible array sizes

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