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how to modify a structure?

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UPT
UPT on 16 Sep 2012
Hello. I initialize (instantiate) a structure like this:
YourStruct = struct(...
'Date', {cell(2208,1)}, ...
'Hour', {zeros(2208,1)}, ...
'DryBulb', {zeros(2208,1)}, ...
'DewPnt', {zeros(2208,1)}, ...
'SYSLoad', {zeros(2208,1)}, ...
'NumDate', {zeros(2208,1)});
'Date' has 92 days, and 'Hour' has 24 hours, from 1 to 24. How can I express 'Date' and 'Hour' in serial date numbers and how do I present these serial date numbers in 'NumDate'? Thank you.
  7 Comments
UPT
UPT on 16 Sep 2012
Edited: Oleg Komarov on 16 Sep 2012
sorry again for my mistakes Walter Roberson: here is my new post:
data = struct('Date', {cell(2208,1)}, 'Hour', {zeros(2208,1)}, 'DryBulb', {zeros(2208,1)}, 'DewPnt', {zeros(2208,1)}, 'SYSLoad', {zeros(2208,1)}, 'NumDate', {zeros(2208,1)});
'Date' has 92 days and 'Hour' has 24 hours,from 1 to 24.how can i express 'Date' and 'Hour' in serial date numbers and to present these serial date numbers in 'NumDate'?
Walter Roberson
Walter Roberson on 16 Sep 2012
Blank line before and after the code. Indent the code.

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Answers (1)

Walter Roberson
Walter Roberson on 16 Sep 2012
NumDate = Data.Date + (Data.Hour - 1) / 24;
  5 Comments
UPT
UPT on 17 Sep 2012
for each day i want to have 24 date serial numbers (a date serial number for each hour).could please you tell me how i can do that?...note:im a new user in matlab and i make some basic mistakes,so dont be upset if i dont understand all what you say..anyway,this is the fourth time you help me and im very grateful to you..:)
Walter Roberson
Walter Roberson on 17 Sep 2012
Your Hour field is the same length as your Date field, which suggests you want exactly 1 hour conversion for each Date converted, rather than wanting to create 24 hour conversions for each Date converted.
data.NumDate = datenum(Data.Date) + (Data.Hour - 1) / 24;
except that you might need to add an additional parameter to datenum() in order to indicate the date format.

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