How to break an image into blocks?
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I have an image with (643x643) dimensions , and i need to split it horizontally and vertically into 100 sub images,so that each sub image is (64x64)pixels using matlab code .The sub images are blocks with (64x64) pixels ,so the height and the width of each block is equal 64
Answers (1)
Fabio Freschi
on 10 Oct 2019
Edited: Fabio Freschi
on 10 Oct 2019
Three assumprions
1) the image is a 2d matrix
2) the row/cols have 64x3, 3x64 and 3x3 blocks
3) you want 10 sub images, not 100
% A is your image
B = mat2cell(A,[64*ones(1,10) 3],[64*ones(1,10) 3]);
B is a 11x11 cell array with your sub images. You can access each of them with B{i,j}.
If the image is a 3d matrix (643x643x3), just add the third dimension to mat2cell:
B = mat2cell(A,[64*ones(1,10) 3],[64*ones(1,10) 3],3);
8 Comments
Rik
on 13 Oct 2019
You need to tell Matlab how to split up your array. If I tell you to divide 10 objects in 3 groups of 3, you will ask me what to do with object 10. The code below will show you in multiple steps how to create the grouping for each dimension. Make sure to understand what each line of code does, and look at the contents of D{1} and D{2}.
A = rand(634,643);
D=cell(1,2);
for dim=1:2
D{dim}=64*ones(1,floor(size(A,dim)/64));
if sum(D{dim})~=size(A,dim)
%extend with remainder
D{dim}(end+1)=size(A,dim)-sum(D{dim});
end
end
B=mat2cell(A,D{1},D{2});
Image Analyst
on 13 Oct 2019
No one has actually directly asked what you want to do with the blocks. So I will, because it probably matters. What do you plan on doing with the blocks once you have them?
And again, like the others keep stressing to you, you will not have blocks all the same size if you have an image 643 pixels wide and use blocks 64 pixels wide. What are your plans for the different sized block?
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