FFT based adaptive MVDR beamforming
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Hello,
I have a small question on FFT based adaptive beamforming based on Spectral Matrix Inversion technique.
I have estimated the Spectral Matrix (Sxx) from my data by dividing it into blocks and averaging them for each bin, to get sufficient rank on the matrix.
Now my question is :
To produce the MVDR weighting vector (8x1 vector in my case since I have 8 microphones) for each bin, I multiply the inverse of Sxx for each bin (say bin#1) with the steering vector 'a' given by exp(i*2*pi*D*omega), where D is the set of time delays(8x1 vector) pointing towards look direction(say +10°). Here what should be 'omega'? Isit equal to the first frequency bin of data from first channel and so on for all the bins? please clarify.
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Answers (3)
Honglei Chen
on 24 Sep 2012
Looks like you are doing subband MVDR. It should be the frequency for each corresponding band.
11 Comments
Honglei Chen
on 26 Sep 2012
For an arbitrary shaped array (sounds like your situation), I don't think there are a lot of theoretical results. It's a design problem you need to solve.
zohar
on 9 Oct 2012
Hi zozo,
You allready posted a question
http://www.mathworks.com/matlabcentral/answers/39458-covariance-matrix-stimation-in-mvdr-beamforming
Combining the two questions ,evrything looks OK!
1) What is the shape of the array ? In the previous question you mentiond that it's spherical shape.
2) It's seems that in step 9 you want to go back to time domain, I do not understand what you doing ! can you supply the relevant matlab code ?
3) Insted of steps 7-9 calc P - the narrowband power spectrum, where P is:
P = zeros(Nbins,Nbeam)
for k = 1:Nbins
% for each bin
% calc A - sterring matrix.
% calc IRf - Inverse spatial covariance matrix.
P(k,:) = real(Nbeam./sum(A'*IRf*A));
end
Now calc
Plog = 20*log10(P);
mesh(Plog);
And let me know what the result is...
3 Comments
zohar
on 24 Oct 2012
Nbeam is number of beams acorrding to sterring matrix. Let me help you do step (3) and supply matlab code I think yor are missing something befor ifft .
Have fun
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