How does imflatfield work?

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Julia Kelly
Julia Kelly on 12 Nov 2019
Commented: Arthur Redgate on 1 Sep 2023
What formula does the imflatfield function use when used with a matrix as input?
For example, I have an image of surface temperature (attached) = bad_img. If I apply
corr_img = imflatfield(bad_img,100);
How can I reproduce corr_img without using imflatfield? I know that the gaussian filter can be generated using
iblur=imgaussfilt(bad_img, 100);
But what are the next steps?
  1 Comment
William Nitsch
William Nitsch on 2 Oct 2021
Iout = Iin * mean(gaussian_blurred_img)/gaussian_blurred_img

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Answers (1)

DGM
DGM on 2 Oct 2021
Edited: DGM on 2 Oct 2021
William's comment is close. Probably close enough to be useful, but not quite exactly the same as what imflatfield() does.
A = imread('printedtext.png');
sigma = 30;
% this is the reference
output1 = imflatfield(A,sigma);
% this is a replication of the behavior
A = im2single(A); % non-double images are converted to single
% this is the default filter size, but it can be set explicitly too
blurred = imgaussfilt(A,sigma,'padding','symmetric','filtersize',2*ceil(2*sigma)+1);
output2 = A*mean(A(:),'omitnan')./blurred; % mean of A, not of blurred image
output2 = im2uint8(output2);
immse(output1,output2) % show that the results match
ans = 0
Bear in mind that if you want to exactly replicate the behavior, there are other things that happen (e.g. dealing with NaNs and Inf) that need to also be considered. You can always just open imflatfield() and read it.
EDIT: oof. This wouldn't be the first time I absentmindedly answered a dead question...
  1 Comment
Arthur Redgate
Arthur Redgate on 1 Sep 2023
I appreciate your answer as it's helped me 5 years after the asking of the original question!

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