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Iteration cycle of a code

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Hi !!! Have a nice day.
I have a code that starts with the generation of a matrix A,
after a numerical process at the end I have a matrix B
A = [a, b, c,… ..
q, w, r,….];
instructions
instructions
instructions
instructions
instructions
instructions
B = [d, e, f,….
and, u, I, ...];
At the end of the numerical process I have matrix B, immediately
the values of B are assigned to A in this way
A = B
What instruction I need to do to generate this cycle N times, that this; the results of B introduce them to input A?
I hope you understand what I want to do
Thank you

  6 Comments

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Ricardo Gutierrez
Ricardo Gutierrez on 5 Dec 2019
No, I don't want to concatenate. I want to update the values of A with the resulting matrix B, in each cycle(n times). But this I have not been able to achieve.
Adam Danz
Adam Danz on 5 Dec 2019
" I want to update the values of A with the resulting matrix B"
So you want to completely overwrite A with whatever is stored in B on each iteration.
But this I have not been able to achieve"
Why not? What specific problems have you faced?
Again, a simple example of expected input and outputs usually saves quite a bit of time and dialog.
Ricardo Gutierrez
Ricardo Gutierrez on 5 Dec 2019
You are right.
I should check my code.
Thank you very much for your patience and your help.

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Accepted Answer

meghannmarie
meghannmarie on 5 Dec 2019
Can you show your code? Make sure you are initally setting A before the for loop. If I am understanding the problem, it should look something like this:
A = [a,b,c;q,w,r];
for n = 1:5
% instructions
% instructions
% instructions
B = [d,e,f;l,m,n]
A = B;
end

  5 Comments

Show 2 older comments
Ricardo Gutierrez
Ricardo Gutierrez on 5 Dec 2019
No, I don't want to concatenate. I want to update the values of A with the resulting matrix B, in each cycle. But this I have not been able to achieve.
meghannmarie
meghannmarie on 5 Dec 2019
Is variable A part of the input into building variable B? There must be an error in your code, I do not know how to troubleshoot without code.
Ricardo Gutierrez
Ricardo Gutierrez on 5 Dec 2019
Thank you very much.
You are right there must be some error in my code.
Thank you for your patience and attention.

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