Calculating the sum of each row in a matrix.
51 views (last 30 days)
Show older comments
Hi,
I have a code like this:
X = [1 2 3 4 5;
3 5 7 9 11;
2 4 6 8 10;
3 9 12 15 18];
minx = min(X, [ ], 2); %min of each vector
maxx = max(X, [ ], 2); %max of each vector
result = X >= reshape(minx, 1, 1, [ ]) & X <= reshape(maxx, 1, 1, [])
When i run it,
result is 4x5x4 logical and
val(:,:,1) =
1 1 1 1 1
1 1 0 0 0
1 1 0 0 0
1 0 0 0 0
Here i have a question.
I would like to see the sum of each row with names.
In val(:,:,1), the sum of first row= A11, sum of second row= A12, sum of third row= A13 and sum of fourth row=A14 .
Likewise for
val(:,:,2) =
0 0 1 1 1
1 1 1 1 1
0 1 1 1 1
1 1 0 0 0
sum of first row= A21, sum of second row= A22,...
I tried to do this with creating a 4X4 matrix A which consist of the sum values A11, A12, A13 A14, .... But i cant do it.
Any help is appreciated.
3 Comments
Answers (1)
Sourav Bairagya
on 12 Feb 2020
You can use 'sum' function to compute sum for each row and then can apply 'squueze' function to remove the singleton dimension (i.e. dimension with length 1). After that you can take transpose of the result and you will get the desired output.
val = sum(result,2);
out = squeeze(val);
A = out';
You can leverage these links for further information:
See Also
Categories
Find more on Logical in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!