how can I get successive maximum value from this code?

Hi all, Could you please help me to get the successive value from this code?

Here, I want to get the maximum value of from 2 values. e.g. when it is 5th iteration (i = 5) that time the maximum value should be 80 because when it was i = 3 that time we got the max value 60 from i = 1 and it is remained at i = 2.

More specifically what I want to get from this codes,

when it is i = 1

B = max(40,60) = 60

when i = 2

B = max (60,30) = 60

when i = 3

B = max (60,80) = 80

when i = 4

B = max(80,70) = 80

when i = 5

B = max(80,50) = 80

when i = 6

B = max(80,90) = 90

when i = 7

B = max(90,30) = 90

But in this code I am getting something different at i = 5 which is 70 but I need to get 80 at this time.

Thank you in advance.

A = [40, 60, 30, 80, 70, 50, 90, 30];
for i = 1:length(A)-1
    B = max(A(i:i+1));
    C = A(i+1);
    if C/B < 0.7
        x = C/10;
    else
        x = C/5;
    end
end

Answer 1

[David Hill]

Why not index B and x? Otherwise, you are overriding their values each time the loop is run. For i =5, max ([70 50]) = 70! Not sure why you thing it should be 80.

A = [40, 60, 30, 80, 70, 50, 90, 30];
for i = 1:length(A)-1
    B(i) = max(A(i:i+1));
    C = A(i+1);
    if C/B(i) < 0.7
        x(i) = C/10;
    else
        x(i) = C/5;
    end
end

[Mohmmad Abu Yousuf]

Thank you Sir I got it for index term.

and the other one is,

for every max value it will take the previous max value and the current value of i.

I mean for i = 5, previous maximum value is 80 and the current value is 50 so the current maxmum value should be 80.

At the end of simulation the B matrix should be like this,

B = [60,60,80,80,80,90,90]

How can I edit this code to get likewise Sir.