Response surface method in Matlab

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Arash
Arash on 2 Mar 2020
Answered: Thonn Homsnit on 10 May 2022
Hi.
I have 6 independent variable and one dependent variable. I want to fit a response surface to the data by for exp a second order polynomial, when I open curve fitting toolbox, There is only two space for the input variable. can anyone help me about this. How can I do this fit in matlab?
Thank you in advance for your time.

Accepted Answer

darova
darova on 2 Mar 2020
Look here
  4 Comments
Arash
Arash on 4 Mar 2020
Here you have two independent variable X and Y and Z as the dependent variable. How can I apply this to a four independent variable for example [x1 x2 x3 x4 ];
I don't know my equation to use the custom option. I want to get the euqation from thisw method [polynomial with degree of 2] from my data.
darova
darova on 4 Mar 2020
fit toolbox can't handle such task. Maybe you want griddedInterpolant

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More Answers (1)

Thonn Homsnit
Thonn Homsnit on 10 May 2022
I faced the same problem as the author. But I have just figured it out !
I use the 'fitnlm' function with the user defined function with handle like this
modelFun = @(b1,x1)( ...
+b1(1).*x1(:,1) ...
+b1(2).*x1(:,2) ...
+b1(3).*x1(:,3)...
+b1(4).*x1(:,4)...
+b1(5).*x1(:,1).*x1(:,2) ...
+b1(6).*x1(:,1).*x1(:,3) ...
+b1(7).*x1(:,1).*x1(:,4) ...
+b1(8).*x1(:,2).*x1(:,3) ...
+b1(9).*x1(:,2).*x1(:,4) ...
+b1(10).*x1(:,3).*x1(:,4) ...
+b1(11).*x1(:,1).*x1(:,1) ...
+b1(12).*x1(:,2).*x1(:,2) ...
+b1(13).*x1(:,3).*x1(:,3) ...
+b1(14).*x1(:,4).*x1(:,4) ...
+b1(15) ...
);
beta0 = zeros(15,1); %%% initial coefficient value %%%%
mdl1 = fitnlm(x1,y1,modelFun,beta0);
b1 = table2array(mdl1.Coefficients(:,"Estimate"));
x1 is predictor matrix and y1 is target vector. you can solve the b1 matrix which is the coefficient of this function. Another tool is using MBC toolbox. But the documentation is very old and i cannot find the algorithm behind the toolbox.
Hope it helps.

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