How can I solve this error when I use Trapz ?
1 view (last 30 days)
Show older comments
ibrahim alzoubi
on 17 Apr 2020
Commented: Ameer Hamza
on 17 Apr 2020
I keep getting this error when I run my program.
err = 1-y; %Define error signal
t = 0 : 0.01 :30;
ise = trapz (1,err.^2);
-------
Error using trapz (line 47)
Dimension argument must be a positive integer scalar within indexing range.
Undefined operator '.^' for input arguments of type 'timeseries'.
y here is output data from a block diagarm simulink.
any solutions?
2 Comments
Accepted Answer
Ameer Hamza
on 17 Apr 2020
Try this
err = 1 - y.Data; %Define error signal
ise = trapz(y.Time, err.^2);
2 Comments
More Answers (0)
See Also
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!