Confusion with interp3 and interpn

Hi,
According to my teacher, "for a matrix indexed as [M, N, P], the axis variables must be given in the order N, M, P" in relation to the swaping of variables at the interp3 line:
[X, Y, Z] = size(data);
ts= [20 30 20]
[x, y, z] = ndgrid((1:X)/X, (1:Y)/Y, (1:Z)/Z);
[x2, y2, z2] = ndgrid((1:ts(1))/(ts(1)), (1:ts(2))/(ts(2)), (1:ts(3))/(ts(3)));
test1= interp3(y, x, z, data, y2, x2, z2, 'linear');
However, I couldn't find this info on the function's page, nor it makes any sense to me (even though the computation seems correct!).
Any help welcome, thank you,
TS

5 Comments

I don't understand the question. What are you asking?
Why the order of variables should be "y,x,z".
Did you try 'x,y,z' order? I think the result should be the same
Yes, of course I did, but it outputs an error:
Error using interp3 (line 150)
Input grid is not a valid MESHGRID.
Maybe it's the answer on your question

Sign in to comment.

 Accepted Answer

Steven Lord
Steven Lord on 24 Apr 2020
I think reading through this documentation page may be of use to you, especially the examples in the Grid Representation section.

1 Comment

Still, Why the order of variables should be "y,x,z"?

Sign in to comment.

More Answers (1)

here is an example
[x,y] = meshgrid(1:5);
z = x.^2 + y.^2/2;
[x1,y1] = meshgrid(1:0.5:5);
z1 = interp2(x,y,z,x1,y1); % standart interpolation
z2 = interp2(y',x',z,y1',x1'); % interpolation y x
surf(x,y,z,'facecolor','none')
hold on
plot3(x1(:),y1(:),z1(:),'.r')
plot3(x1(:),y1(:),z2(:),'ob')
hold off
legend('original surface',...
'standard interpolation',...
'y x interpolation','location','north')
axis vis3d

2 Comments

Thanks, however, you are using interp2, and not interp3. Do the same with interp3 and you will get an error, I would expect. See here: https://groups.google.com/forum/#!topic/comp.soft-sys.matlab/xlinA3xsxT8 "Does interp3 switch X and Y".

Sign in to comment.

Categories

Find more on Interpolation in Help Center and File Exchange

Products

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!