Displacement Graph (How to center it) ?

Hello everyone.

I am new to MatLab and I am working on a code which is supposed to calculated the displacement of the aircraft from top view.

I have managed to write the code and plot X and Y coordinates which look like this (Picture below)

I would like to center the graph. What I mean by that is I want 0 Y coordinate to be in the middle of the circle and not at the bottom. I would really appreciate any help!

Here is the code:

clc;
clear all;
close all;

M = 8000; % Mass of the plane (kg)
V = 80; %Velocity (m/s)
R = 250; %Radius of the turn (m)
g = 9.81; %Gravitaional Acceleration (m/s)
thetaDeg = 0;
w = V/R %Angular velocity
W = g*M %Weight of the plane. (N)

%solve 360turn equation to find max t
t360 = 2*(pi/w)
dt = 0.1; %time step 
t = 0:dt:t360;
%find n and theta
n = sqrt((V^2/(R*g))^2+1)
thetaRad = acos(1/n)
thetaDeg = (thetaRad/pi)*180
F = W*n*sin(thetaRad)

%Vx = zeros(1,length(t));
%Vy = zeros(1,length(t));
%Xp = zeros(1,length(t));
%Yp = zeros(1,length(t));
Vx = V*sin(thetaRad);
Vy = V*sin(thetaRad);
Xc = zeros(1,20); 
Yc = zeros(1,20);
Xc(1) = 0;
Yc(1) = 0;
Crs = zeros(1,length(t));
Crs(1) = 0
CrsDeg = zeros(1,length(t));
CrsDeg(1) = 0


for n=2:length(t)
    Crs(n) = Crs(n-1)+(w*dt)
    Yc(n) = Yc(n-1)+(dt*Vy*sin(Crs(n)))
    Xc(n) = Xc(n-1)+(dt*Vx*cos(Crs(n)))
    CrsDeg(n) = (Crs(n)/pi)*180
end

plot(Xc,Yc)

%rad = pi*theta/180;
% L = cos(th) = W
% L = nW
% cos(th) = (1/n)

Answer 1

[Srivardhan Gadila]

If your concern is regarding the plot only then the quick work around would be to replace

plot(Xc,Yc)

with

plot(Xc,Yc-max(Yc)/2)

If this is not what you are looking for, then can you explain the issue more specifically?

Answer 2

[Image Analyst]

Use ylim after you plot it:

ylim([-500, 500]);