Extracting the closest possible value having the same indices

t1 = 2.3
t2 = 5.6

%its is a 2*7*1*10*10*15*8 matrix
p = period_arr(1,:,:,:,:,:,:); % this is of the form p = period_arr(i1, i2, i3, i4, i5, i6, i7);
n = period_arr(2,:,:,:,:,:,:); % this is of the form n = period_arr(i1, i2, i3, i4, i5, i6, i7);

dist_p = abs(p - t1);
[min_dist_p, idx_p] = min(dist_p(:));

dist_n = abs(n - t2);
[min_dist_n, idx_n] = min(dist_n(:));

c_tp = p(idx_p);
c_tn = n(idx_n);

So based on the minimum distance I get the closest value, and it is working fine.

But, I have a problem where I have to get only the closest value where the indices i4 of p = i4 of n and i5 of p = i5 of n. It should regulate the same value for both p and n.

How can I do that? Please help me out. I've been stuck on this problem from 2 days.

For example, I can have

2.6 = period_arr(1,:,:,a,b,:,:)
7.8 = period_arr(2,:,:,a,b,:,:)

[Ganesh Kini]

Output example

tp = [ 2.2, 2.4, 2.5, 2.6 ]

Looking at this, the closest value is 2.2 or 2.4 w.r.t t1

2.2 = period`_arr(i1, i2, i3, 4, 5, i6, i7)

2.4 = period`_arr(i1, i2, i3, 3, 1, i6, i7)

tn = [ 5.2, 5.4, 7.5, 5.8 ]

Looking at this, the closest value is 5.4 or 5.8 w.r.t t2

5.4 = period`_arr(i1, i2, i3, 1, 2, i6, i7)

5.8 = period`_arr(i1, i2, i3, 4, 5, i6, i7)

so i should choose 2.2 and 5.8 as the close c_tp and c_tn respectively

since the the indices i4 of p = i4 of n and i5 of p = i5 of n. the other i values can take any value

[Ganesh Kini]

Can someone please help me out in this regard?

[Stephen23]

1. do not split the data into separate variables: keep them in vectors/matrices.
2. use the euclidean distance to find the closest set of points.

[Ganesh Kini]

Hi Stephen,

1) P and N should be two independent variables. I have to take it that way

2) could you please post some links regarding those

[Stephen23]

https://www.mathworks.com/help/matlab/ref/norm.html#mw_c85cbe4a-bca2-4700-9307-00c60bb3d427

https://en.wikipedia.org/wiki/Euclidean_distance

[Ganesh Kini]

I have checked this yesterday, but this is not the solution that i am looking for.