How to define a new variable in a table, Part 3
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I have a table test
date breakfast lunch
1/2/2020 10 20
1/3/2020 5 25
1/4/2020 8 20
Just for the sake of an exmple, I want to calculate a new variable with the formula
test.newvariable(k) = test.lunch(k)/sqrt(test.breakfast(k))
Can one define this new variable without using a loop?
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Accepted Answer
madhan ravi
on 19 Jun 2020
Edited: madhan ravi
on 19 Jun 2020
Remove (k) and replace / with ./
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