Categorizing array elements based on percentage

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I have an array, whose odd indices are to be divided into 4 categories based on some predefined percentage.For example, say X = [1,2.....20],odd_ind = [1 3 5...17 19], among which the first 40% are to be categorized as 1, next 30% as 2, next 20% as 3 and next 10% as 4.Could anyone guide me through this?I am a beginner and need some help with this.
Thanks in advance.
  3 Comments
Walter Roberson
Walter Roberson on 26 Jun 2020
Is that first 40% and so on by value, or by index?

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Accepted Answer

Rasul Khan
Rasul Khan on 26 Jun 2020
You can have the four categories separated this way.
a = 1 : 20;
odd_ind = a(1 : 2 : end);
category1 = odd_ind( (1 : end) <= 0.4 * end );
category2 = odd_ind((1:end) > 0.4 * end & (1 : end) <= 0.7 * end );
category3 = odd_ind((1:end) > 0.7 * end & (1 : end) <= 0.9 * end );
category4 = odd_ind((1:end) > 0.9 * end );

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