solve quadratic for max & min
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how to solve this quadratic equation for Max & Min values:
A1*x1^2 + B1*x1*x2 + C1*x2^2 + D1*x1 + E1*x2 + F1
can't find a proper explanation. Please!
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Walter Roberson
on 5 Dec 2012
If A1 is negative, then for every finite x2, the mininum is at x1 = +/- infinity.
If C1 is negative, then for every finite x1, the minimum is at x2 = +/- infinity.
Otherwise, for every finite x1 and finite x2, the minimum is at
x1 = (B1*E1-2*C1*D1)/(-B1^2+4*C1*A1)
x2 = -(2*A1*E1-D1*B1)/(-B1^2+4*C1*A1)
If A1 and C1 are opposite signs, then when x1 and x2 are both infinite, the minimum is undefined.
2 Comments
Walter Roberson
on 5 Dec 2012
Edited: Walter Roberson
on 5 Dec 2012
What values do you have for x1min, x1max, x2min, x2max, and delta? You might be in a situation where one of x1min:delta:x1max or x2min:delta:x2max are empty, in which case Z would come out empty.
Also, what are z1 and z2 ?
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