Given that t is in increments 0.1 and goes from 0 to 20, how can I make a variable that consists of 5t^2?

23 views (last 30 days)
First I made x as:
>> t = 0:0.1:20
I have tried numerous ways to get a variable consisting of 5t^2 and have the same result. It ends up generating a 1x201 row vector with values from 0 to 2.
I believe it is only multiplying 5 by the 0.1 increment but not the actual values. Any solutions?
  2 Comments
jessupj
jessupj on 14 Sep 2020
Edited: jessupj on 14 Sep 2020
5.*(0:0.1:20).^2
also perhaps try to adjust the way the output is showing, since the results are in range [0,2000] and it may look like [0,2] with a multiplier
format long g

Sign in to comment.

Answers (1)

David Hill
David Hill on 14 Sep 2020
a=5*t.^2;
  1 Comment
Tyler Bodnarik
Tyler Bodnarik on 14 Sep 2020
For some reason its not giving me what 5t^2 should be. It keeps giving me a 1x201 row vector with values 0 to 2. It should have all the values of t get squared and multiplied by 5.

Sign in to comment.

Categories

Find more on Matrices and Arrays in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!